(2b+9)=2(b+9/2)

Solution for (2b+9)=2(b+9/2) equation:

(2b+9)=2(b+9/2)

We move all terms to the left:

(2b+9)-(2(b+9/2))=0

We add all the numbers together, and all the variables

(2b+9)-(2(+b+9/2))=0

We get rid of parentheses

2b-(2(+b+9/2))+9=0

We multiply all the terms by the denominator


2b*2))-(2(+b+9+9*2))=0

We add all the numbers together, and all the variables

2b*2))-(2(b+27))=0

We add all the numbers together, and all the variables

2b*2))-(2(b=0

Wy multiply elements

4b^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{0}{8}=0$