(2b+5)/2=b-1

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Solution for (2b+5)/2=b-1 equation: 



(2b+5)/2=b-1

We move all terms to the left:

(2b+5)/2-(b-1)=0

We get rid of parentheses

(2b+5)/2-b+1=0

We multiply all the terms by the denominator


(2b+5)-b*2+1*2=0

We add all the numbers together, and all the variables

(2b+5)-b*2+2=0

Wy multiply elements

(2b+5)-2b+2=0

We get rid of parentheses

2b-2b+5+2=0

We add all the numbers together, and all the variables

7!=0

There is no solution for this equation

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