(2a-3b)(3b)/3c*c

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Solution for (2a-3b)(3b)/3c*c equation: 


x in (-oo:+oo)

c*c*((3*b*(2*a-(3*b)))/3) = 0

c*c*((3*b*(2*a-3*b))/3) = 0

(3*b*c^2*(2*a-3*b))/3 = 0

x belongs to the empty set

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