(2a-1)/(3-5a)=10

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Solution for (2a-1)/(3-5a)=10 equation: 


D( a )

3-(5*a) = 0

3-(5*a) = 0

3-(5*a) = 0

3-5*a = 0

3-5*a = 0 // - 3

-5*a = -3 // : -5

a = -3/(-5)

a = 3/5

a in (-oo:3/5) U (3/5:+oo)

(2*a-1)/(3-(5*a)) = 10 // - 10

(2*a-1)/(3-(5*a))-10 = 0

(2*a-1)/(3-5*a)-10 = 0

(2*a-1)/(3-5*a)+(-10*(3-5*a))/(3-5*a) = 0

2*a-10*(3-5*a)-1 = 0

52*a-31 = 0

(52*a-31)/(3-5*a) = 0

(52*a-31)/(3-5*a) = 0 // * 3-5*a

52*a-31 = 0

52*a-31 = 0 // + 31

52*a = 31 // : 52

a = 31/52

a = 31/52

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