If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
((2*a-1)*(2*b-1)*(2*c-1))/7 = 0
x belongs to the empty set
| 4t^2+x+8=0 | | 8x=6x^2 | | X/4-10=5 | | x-2=11-2x | | y=ln(4-x)+ln(4+x) | | 3/4(576-x) | | a=5jz | | -3x=21+3x | | (x+2)*(x-3)-ln(16-x^2)=0 | | (x+2)*(x-2)-ln(16-x^2)=0 | | .08+.25(x-6)=.03(x+10) | | F(x)=4x^3-2x^2+5x-1 | | y^2-2xy=0 | | 0.25x+0.60(20-x)=10 | | (x+2)*(x-2)=ln(16-x^2) | | 5(-3x+5)=-6 | | 9+6=42x | | -6-4r=-2 | | -9/5m=8 | | 7*(x+2)-2=65 | | y^2=-x^2-3xy+10 | | -12c+5=1.4 | | 6/X=3/25 | | f^8(x)=cos(2x) | | -2=5a+1 | | ln(x^2-3)=2 | | 8=5a+1 | | 2(2r+q)=8 | | -4-x=-3x | | 2x+3y=4p-x | | 7x^2-35x+16=0 | | -5(x/4)=-50 |