(2a+c)+(a+b-c)=

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Solution for (2a+c)+(a+b-c)= equation:


Simplifying
(2a + c) + (a + b + -1c) = 0

Remove parenthesis around (2a + c)
2a + c + (a + b + -1c) = 0

Remove parenthesis around (a + b + -1c)
2a + c + a + b + -1c = 0

Reorder the terms:
2a + a + b + c + -1c = 0

Combine like terms: 2a + a = 3a
3a + b + c + -1c = 0

Combine like terms: c + -1c = 0
3a + b + 0 = 0
3a + b = 0

Solving
3a + b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1b' to each side of the equation.
3a + b + -1b = 0 + -1b

Combine like terms: b + -1b = 0
3a + 0 = 0 + -1b
3a = 0 + -1b
Remove the zero:
3a = -1b

Divide each side by '3'.
a = -0.3333333333b

Simplifying
a = -0.3333333333b

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