(2a+3)=(4a-8)=7

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Solution for (2a+3)=(4a-8)=7 equation: 



(2a+3)=(4a-8)=7

We move all terms to the left:

(2a+3)-((4a-8))=0

We get rid of parentheses

2a-((4a-8))+3=0



We calculate terms in parentheses: -((4a-8)), so:

(4a-8)

We get rid of parentheses

4a-8

Back to the equation:

-(4a-8)



We get rid of parentheses

2a-4a+8+3=0

We add all the numbers together, and all the variables

-2a+11=0

We move all terms containing a to the left, all other terms to the right

-2a=-11

a=-11/-2

a=5+1/2

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