(2B+8)+(B)+(3B)=128

Solution for (2B+8)+(B)+(3B)=128 equation:

Simplifying
(2B + 8) + (B) + (3B) = 128

Reorder the terms:
(8 + 2B) + (B) + (3B) = 128

Remove parenthesis around (8 + 2B)
8 + 2B + (B) + (3B) = 128
8 + 2B + B + (3B) = 128

Combine like terms: 2B + B = 3B
8 + 3B + (3B) = 128

Combine like terms: 3B + (3B) = 6B
8 + 6B = 128

Solving
8 + 6B = 128

Solving for variable 'B'.

Move all terms containing B to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + 6B = 128 + -8

Combine like terms: 8 + -8 = 0
0 + 6B = 128 + -8
6B = 128 + -8

Combine like terms: 128 + -8 = 120
6B = 120

Divide each side by '6'.
B = 20

Simplifying
B = 20