(28b-3)-9(3b+2)=-6

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Solution for (28b-3)-9(3b+2)=-6 equation: 



(28b-3)-9(3b+2)=-6

We move all terms to the left:

(28b-3)-9(3b+2)-(-6)=0

We add all the numbers together, and all the variables

(28b-3)-9(3b+2)+6=0

We multiply parentheses

(28b-3)-27b-18+6=0

We get rid of parentheses

28b-27b-3-18+6=0

We add all the numbers together, and all the variables

b-15=0

We move all terms containing b to the left, all other terms to the right

b=15

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