(28/2x+5)+(3/x)=4

Solution for (28/2x+5)+(3/x)=4 equation:

(28/2x+5)+(3/x)=4

We move all terms to the left:

(28/2x+5)+(3/x)-(4)=0


Domain of the equation: 2x+5)!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(28/2x+5)+(+3/x)-4=0

We get rid of parentheses

28/2x+3/x+5-4=0

We calculate fractions


28x/2x^2+6x/2x^2+5-4=0

We add all the numbers together, and all the variables

28x/2x^2+6x/2x^2+1=0

We multiply all the terms by the denominator


28x+6x+1*2x^2=0

We add all the numbers together, and all the variables

34x+1*2x^2=0

Wy multiply elements

2x^2+34x=0

a = 2; b = 34; c = 0;
Δ = b2-4ac
Δ = 342-4·2·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-34}{2*2}=\frac{-68}{4}
=-17
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+34}{2*2}=\frac{0}{4}
=0
$