(27x/11)+(5x/22)=(22/59)

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Solution for (27x/11)+(5x/22)=(22/59) equation:



(27x/11)+(5x/22)=(22/59)
We move all terms to the left:
(27x/11)+(5x/22)-((22/59))=0
We add all the numbers together, and all the variables
(+27x/11)+(+5x/22)-((+22/59))=0
We get rid of parentheses
27x/11+5x/22-((+22/59))=0
We calculate fractions
175230x^2/()+16225x^2/()+()/()=0
We add all the numbers together, and all the variables
175230x^2/()+16225x^2/()+1=0
We multiply all the terms by the denominator
175230x^2+16225x^2+1*()=0
We add all the numbers together, and all the variables
191455x^2=0
a = 191455; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·191455·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{382910}=0$

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