(27x+3-(9x-5))=10x-2

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Solution for (27x+3-(9x-5))=10x-2 equation: 



(27x+3-(9x-5))=10x-2

We move all terms to the left:

(27x+3-(9x-5))-(10x-2)=0

We get rid of parentheses

(27x+3-(9x-5))-10x+2=0



We calculate terms in parentheses: +(27x+3-(9x-5)), so:

27x+3-(9x-5)

determiningTheFunctionDomain
27x-(9x-5)+3

We get rid of parentheses

27x-9x+5+3

We add all the numbers together, and all the variables

18x+8

Back to the equation:

+(18x+8)



We add all the numbers together, and all the variables

-10x+(18x+8)+2=0

We get rid of parentheses

-10x+18x+8+2=0

We add all the numbers together, and all the variables

8x+10=0

We move all terms containing x to the left, all other terms to the right

8x=-10

x=-10/8

x=-1+1/4

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