(24/c)-18c=-24

Solution for (24/c)-18c=-24 equation:

(24/c)-18c=-24

We move all terms to the left:

(24/c)-18c-(-24)=0


Domain of the equation: c)!=0

c!=0/1

c!=0

c∈R


We add all the numbers together, and all the variables

(+24/c)-18c-(-24)=0

We add all the numbers together, and all the variables

-18c+(+24/c)+24=0

We get rid of parentheses

-18c+24/c+24=0

We multiply all the terms by the denominator


-18c*c+24*c+24=0

We add all the numbers together, and all the variables

24c-18c*c+24=0

Wy multiply elements

-18c^2+24c+24=0

a = -18; b = 24; c = +24;
Δ = b2-4ac
Δ = 242-4·(-18)·24
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-48}{2*-18}=\frac{-72}{-36}
=+2
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+48}{2*-18}=\frac{24}{-36}
=-2/3
$