(24-2x)(30-2x)=432

Solution for (24-2x)(30-2x)=432 equation:

(24-2x)(30-2x)=432

We move all terms to the left:

(24-2x)(30-2x)-(432)=0

We add all the numbers together, and all the variables

(-2x+24)(-2x+30)-432=0

We multiply parentheses ..

(+4x^2-60x-48x+720)-432=0

We get rid of parentheses

4x^2-60x-48x+720-432=0

We add all the numbers together, and all the variables

4x^2-108x+288=0

a = 4; b = -108; c = +288;
Δ = b2-4ac
Δ = -1082-4·4·288
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-108)-84}{2*4}=\frac{24}{8}
=3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-108)+84}{2*4}=\frac{192}{8}
=24
$