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(22/3)=6-(1/12)x
We move all terms to the left:
(22/3)-(6-(1/12)x)=0
Domain of the equation: 12)x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(6-(+1/12)x)+(+22/3)=0
We get rid of parentheses
-(6-(+1/12)x)+22/3=0
We calculate fractions
()/12x)*3)+264x/12x)*3)=0
We can not solve this equation
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