(21x-5)+8(3x-2)-(x-5)=1

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Solution for (21x-5)+8(3x-2)-(x-5)=1 equation: 



(21x-5)+8(3x-2)-(x-5)=1

We move all terms to the left:

(21x-5)+8(3x-2)-(x-5)-(1)=0

We multiply parentheses

(21x-5)+24x-(x-5)-16-1=0

We get rid of parentheses

21x+24x-x-5+5-16-1=0

We add all the numbers together, and all the variables

44x-17=0

We move all terms containing x to the left, all other terms to the right

44x=17

x=17/44

x=17/44

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