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(21x+5)22x=x
We move all terms to the left:
(21x+5)22x-(x)=0
We add all the numbers together, and all the variables
-1x+(21x+5)22x=0
We multiply parentheses
462x^2-1x+110x=0
We add all the numbers together, and all the variables
462x^2+109x=0
a = 462; b = 109; c = 0;
Δ = b2-4ac
Δ = 1092-4·462·0
Δ = 11881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11881}=109$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(109)-109}{2*462}=\frac{-218}{924} =-109/462 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(109)+109}{2*462}=\frac{0}{924} =0 $
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