(21/4)c=(39/4)c+44

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Solution for (21/4)c=(39/4)c+44 equation: 



(21/4)c=(39/4)c+44

We move all terms to the left:

(21/4)c-((39/4)c+44)=0



Domain of the equation: 4)c!=0

c!=0/1

c!=0

c∈R





Domain of the equation: 4)c+44)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

(+21/4)c-((+39/4)c+44)=0

We multiply parentheses

21c^2-((+39/4)c+44)=0

We multiply all the terms by the denominator


21c^2*4)c+44)-((+39=0

Wy multiply elements

84c^3+39=0

We do not support ecpression: c^3

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