(20y-11)+(4y-6)+(7y-7)=360

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Solution for (20y-11)+(4y-6)+(7y-7)=360 equation: 



(20y-11)+(4y-6)+(7y-7)=360

We move all terms to the left:

(20y-11)+(4y-6)+(7y-7)-(360)=0

We get rid of parentheses

20y+4y+7y-11-6-7-360=0

We add all the numbers together, and all the variables

31y-384=0

We move all terms containing y to the left, all other terms to the right

31y=384

y=384/31

y=12+12/31

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