(20x-3)(11x-1)=151

Solution for (20x-3)(11x-1)=151 equation:

(20x-3)(11x-1)=151

We move all terms to the left:

(20x-3)(11x-1)-(151)=0

We multiply parentheses ..

(+220x^2-20x-33x+3)-151=0

We get rid of parentheses

220x^2-20x-33x+3-151=0

We add all the numbers together, and all the variables

220x^2-53x-148=0

a = 220; b = -53; c = -148;
Δ = b2-4ac
Δ = -532-4·220·(-148)
Δ = 133049
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-\sqrt{133049}}{2*220}=\frac{53-\sqrt{133049}}{440}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+\sqrt{133049}}{2*220}=\frac{53+\sqrt{133049}}{440}
$