(20x+10)+(30x-22)+(7x+1)=180

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Solution for (20x+10)+(30x-22)+(7x+1)=180 equation: 



(20x+10)+(30x-22)+(7x+1)=180

We move all terms to the left:

(20x+10)+(30x-22)+(7x+1)-(180)=0

We get rid of parentheses

20x+30x+7x+10-22+1-180=0

We add all the numbers together, and all the variables

57x-191=0

We move all terms containing x to the left, all other terms to the right

57x=191

x=191/57

x=3+20/57

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