If it's not what You are looking for type in the equation solver your own equation and let us solve it.
85;20;42;40;0;0
((1*(1/2))/((x+1)^1))/2
x^2+2*x = 0;x
x
x^2+2*x+2 = 0;x
x
(-2*sin(x)*ln(cos(x)))/cos(x)
| j+4=4j+10 | | -7(x+7)=3x-39 | | 9w=-8+10w | | 8P-6P-P=8 | | 6x+2(x-3)=14 | | x/10=6=0 | | 36=3(v+2)-6v | | -6z=-10-4z | | 8P-6P-P=88 | | -10+v=2v | | 36=3(v+2)-3v | | 3/5x-14=(-8) | | 7*t=28 | | 6x+2(x+3)=4 | | 4-3r=-2 | | 3M-3M+3M-M=18 | | -8r+28=-2(-5r+4) | | 8-x=9x+4(2-x) | | (32-2x)*(20-2x)*x=v(x) | | 2=3h-4 | | (((x^-5)(x^-3))/(x^-1)) | | -2x+3x=-3+14x | | 2j-2=6 | | -9-7n=-(n+3) | | 8a-40=36a+18 | | 8(x+7)=6(x-1) | | 2m^2n^2+2n-12=0 | | 12x-4(2x+4)=10+x-5 | | x^2/4-x=5/4 | | 5*g=15 | | 2v+7(v+3)=-5v-21 | | x+3+2= |