(208+2x)/2=41-20x

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Solution for (208+2x)/2=41-20x equation: 



(208+2x)/2=41-20x

We move all terms to the left:

(208+2x)/2-(41-20x)=0

We add all the numbers together, and all the variables

(2x+208)/2-(-20x+41)=0

We get rid of parentheses

(2x+208)/2+20x-41=0

We multiply all the terms by the denominator


(2x+208)+20x*2-41*2=0

We add all the numbers together, and all the variables

(2x+208)+20x*2-82=0

Wy multiply elements

(2x+208)+40x-82=0

We get rid of parentheses

2x+40x+208-82=0

We add all the numbers together, and all the variables

42x+126=0

We move all terms containing x to the left, all other terms to the right

42x=-126

x=-126/42

x=-3

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