(20/(x+9))+(20/(9-x))=5

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Solution for (20/(x+9))+(20/(9-x))=5 equation: 


D( x )

9-x = 0

x+9 = 0

9-x = 0

9-x = 0

9-x = 0 // - 9

-x = -9 // * -1

x = 9

x+9 = 0

x+9 = 0

x+9 = 0 // - 9

x = -9

x in (-oo:-9) U (-9:9) U (9:+oo)

20/(x+9)+20/(9-x) = 5 // - 5

20/(x+9)+20/(9-x)-5 = 0

(20*(9-x))/((x+9)*(9-x))+(20*(x+9))/((x+9)*(9-x))+(-5*(x+9)*(9-x))/((x+9)*(9-x)) = 0

20*(9-x)+20*(x+9)-5*(x+9)*(9-x) = 0

5*x^2-405+360 = 0

5*x^2-45 = 0

(5*x^2-45)/((x+9)*(9-x)) = 0

(5*x^2-45)/((x+9)*(9-x)) = 0 // * (x+9)*(9-x)

5*x^2-45 = 0

5*x^2 = 45 // : 5

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x in { 3, -3 }

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