(20-2x)(70-2x)=1056

Solution for (20-2x)(70-2x)=1056 equation:

(20-2x)(70-2x)=1056

We move all terms to the left:

(20-2x)(70-2x)-(1056)=0

We add all the numbers together, and all the variables

(-2x+20)(-2x+70)-1056=0

We multiply parentheses ..

(+4x^2-140x-40x+1400)-1056=0

We get rid of parentheses

4x^2-140x-40x+1400-1056=0

We add all the numbers together, and all the variables

4x^2-180x+344=0

a = 4; b = -180; c = +344;
Δ = b2-4ac
Δ = -1802-4·4·344
Δ = 26896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{26896}=164$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-164}{2*4}=\frac{16}{8}
=2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+164}{2*4}=\frac{344}{8}
=43
$