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(20-2x)(45-2x)=350
We move all terms to the left:
(20-2x)(45-2x)-(350)=0
We add all the numbers together, and all the variables
(-2x+20)(-2x+45)-350=0
We multiply parentheses ..
(+4x^2-90x-40x+900)-350=0
We get rid of parentheses
4x^2-90x-40x+900-350=0
We add all the numbers together, and all the variables
4x^2-130x+550=0
a = 4; b = -130; c = +550;
Δ = b2-4ac
Δ = -1302-4·4·550
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-130)-90}{2*4}=\frac{40}{8} =5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-130)+90}{2*4}=\frac{220}{8} =27+1/2 $
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