(20+x)/3=(33+x)/4

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Solution for (20+x)/3=(33+x)/4 equation: 



(20+x)/3=(33+x)/4

We move all terms to the left:

(20+x)/3-((33+x)/4)=0

We add all the numbers together, and all the variables

(x+20)/3-((x+33)/4)=0

We calculate fractions


x/()+(-((x+33)*3)/()=0



We calculate terms in parentheses: +(-((x+33)*3)/(), so:

-((x+33)*3)/(

We multiply all the terms by the denominator


-((x+33)*3)



We calculate terms in parentheses: -((x+33)*3), so:

(x+33)*3

We multiply parentheses

3x+99

Back to the equation:

-(3x+99)



We get rid of parentheses

-3x-99

Back to the equation:

+(-3x-99)



We get rid of parentheses

x/()-3x-99=0

We multiply all the terms by the denominator


x-3x*()-99*()=0

We add all the numbers together, and all the variables

x-3x*()=0

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