(20+x)(20-x)=(x+2)(46-x)=7

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Solution for (20+x)(20-x)=(x+2)(46-x)=7 equation: 



(20+x)(20-x)=(x+2)(46-x)=7

We move all terms to the left:

(20+x)(20-x)-((x+2)(46-x))=0

We add all the numbers together, and all the variables

(x+20)(-1x+20)-((x+2)(-1x+46))=0

We multiply parentheses ..

(-1x^2+20x-20x+400)-((x+2)(-1x+46))=0



We calculate terms in parentheses: -((x+2)(-1x+46)), so:

(x+2)(-1x+46)

We multiply parentheses ..

(-1x^2+46x-2x+92)

We get rid of parentheses

-1x^2+46x-2x+92

We add all the numbers together, and all the variables

-1x^2+44x+92

Back to the equation:

-(-1x^2+44x+92)



We get rid of parentheses

-1x^2+1x^2+20x-20x-44x+400-92=0

We add all the numbers together, and all the variables

-44x+308=0

We move all terms containing x to the left, all other terms to the right

-44x=-308

x=-308/-44

x=+7

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