(20+2x)(20+2x)=0

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Solution for (20+2x)(20+2x)=0 equation: 



(20+2x)(20+2x)=0

We add all the numbers together, and all the variables

(2x+20)(2x+20)=0

We multiply parentheses ..

(+4x^2+40x+40x+400)=0

We get rid of parentheses

4x^2+40x+40x+400=0

We add all the numbers together, and all the variables

4x^2+80x+400=0

a = 4; b = 80; c = +400;
Δ = b2-4ac
Δ = 802-4·4·400
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-80}{8}=-10$

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