(20*x)+(4*x)+(20*4)+(30*30)-(10*10)=308

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Solution for (20*x)+(4*x)+(20*4)+(30*30)-(10*10)=308 equation: 



(20x)+(4x)+(20*4)+(30*30)-(10*10)=308

We move all terms to the left:

(20x)+(4x)+(20*4)+(30*30)-(10*10)-(308)=0

determiningTheFunctionDomain
20x+4x-308+(20*4)+(30*30)-(10*10)=0

We add all the numbers together, and all the variables

20x+4x-308+80+900-100=0

We add all the numbers together, and all the variables

24x+572=0

We move all terms containing x to the left, all other terms to the right

24x=-572

x=-572/24

x=-23+5/6

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