(2/z-8)-(2/z+8)=32/z2-64

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Solution for (2/z-8)-(2/z+8)=32/z2-64 equation: 


D( z )

z^2 = 0

z = 0

z^2 = 0

z^2 = 0

1*z^2 = 0 // : 1

z^2 = 0

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

2/z-(2/z)-8-8 = 32/(z^2)-64 // - 32/(z^2)-64

2/z-(2/z)-(32/(z^2))-8-8+64 = 0

2/z-2*z^-1-32*z^-2-8-8+64 = 0

-32*z^-2 = -48 // : -32

z^-2 = 3/2

-2 < 0

1/(z^2) = 3/2 // * z^2

1 = 3/2*z^2 // : 3/2

2/3 = z^2

z^2 = 2/3 // ^ 1/2

abs(z) = (2/3)^(1/2)

z = (2/3)^(1/2) or z = -(2/3)^(1/2)

z in { (2/3)^(1/2), -(2/3)^(1/2) }

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