(2/z)-(1/2z)=-(3/8)

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Solution for (2/z)-(1/2z)=-(3/8) equation:


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

2/z-((1/2)*z) = -(3/8) // + 3/8

2/z-((1/2)*z)+3/8 = 0

(-1/2)*z+2/z+3/8 = 0

2*z^-1-1/2*z^1+3/8*z^0 = 0

(3/8*z^1-1/2*z^2+2*z^0)/(z^1) = 0 // * z^2

z^1*(3/8*z^1-1/2*z^2+2*z^0) = 0

z^1

(-1/2)*z^2+(3/8)*z+2 = 0

(-1/2)*z^2+(3/8)*z+2 = 0

DELTA = (3/8)^2-(2*4*(-1/2))

DELTA = 265/64

DELTA > 0

z = ((265/64)^(1/2)-(3/8))/(2*(-1/2)) or z = (-(3/8)-(265/64)^(1/2))/(2*(-1/2))

z = 3/8-(265/64)^(1/2) or z = (265/64)^(1/2)+3/8

z in { 3/8-(265/64)^(1/2), (265/64)^(1/2)+3/8}

z in { 3/8-(265/64)^(1/2), (265/64)^(1/2)+3/8 }

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