(2/x-1)-3=(2x+1)/(x-1)

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Solution for (2/x-1)-3=(2x+1)/(x-1) equation:


D( x )

x = 0

x-1 = 0

x = 0

x = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:0) U (0:1) U (1:+oo)

2/x-3-1 = (2*x+1)/(x-1) // - (2*x+1)/(x-1)

2/x-((2*x+1)/(x-1))-3-1 = 0

(-1*(2*x+1))/(x-1)+2/x-3-1 = 0

(-1*x*(2*x+1))/(x*(x-1))+(2*(x-1))/(x*(x-1))+(-3*x*(x-1))/(x*(x-1))+(-1*x*(x-1))/(x*(x-1)) = 0

2*(x-1)-1*x*(2*x+1)-3*x*(x-1)-1*x*(x-1) = 0

x-2*x^2-3*x^2-x^2+3*x+x-2 = 0

4*x-5*x^2-x^2+x-2 = 0

5*x-6*x^2-2 = 0

5*x-6*x^2-2 = 0

5*x-6*x^2-2 = 0

DELTA = 5^2-(-6*(-2)*4)

DELTA = -23

DELTA < 0

1 = 0

1/(x*(x-1)) = 0

1/(x*(x-1)) = 0 // * x*(x-1)

1 = 0

x belongs to the empty set

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