(2/x)/(5/10-x)=12

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Solution for (2/x)/(5/10-x)=12 equation: 


D( x )

5/10-x = 0

x = 0

5/10-x = 0

5/10-x = 0

1/2-x = 0 // - 1/2

-x = -1/2 // * -1

x = 1/2

x = 0

x = 0

x in (-oo:0) U (0:1/2) U (1/2:+oo)

(2/x)/(5/10-x) = 12 // - 12

(2/x)/(5/10-x)-12 = 0

(2*x^-1)/(1/2-x)-12 = 0

(2*x^-1)/(1/2-x)+(-12*(1/2-x))/(1/2-x) = 0

2/x-12*(1/2-x) = 0

12*x+2*x^-1-6 = 0

12*x+2*x^-1-6 = 0

2*(6*x+x^-1-3) = 0

6*x^1+1*x^-1-3*x^0 = 0

(6*x^2-3*x^1+1*x^0)/(x^1) = 0 // * x^2

x^1*(6*x^2-3*x^1+1*x^0) = 0

x^1

6*x^2-3*x+1 = 0

6*x^2-3*x+1 = 0

DELTA = (-3)^2-(1*4*6)

DELTA = -15

DELTA < 0

x in { } 

2 = 0

2/(1/2-x) = 0

2/(1/2-x) = 0 // * 1/2-x

2 = 0

2 = 0

x belongs to the empty set

x belongs to the empty set

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