(2/x)+3=(5/4x)+(25/8)

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Solution for (2/x)+3=(5/4x)+(25/8) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+3 = (5/4)*x+25/8 // - (5/4)*x+25/8

2/x-((5/4)*x)-(25/8)+3 = 0

(-5/4)*x+2/x-25/8+3 = 0

2*x^-1-5/4*x^1-1/8*x^0 = 0

(2*x^0-5/4*x^2-1/8*x^1)/(x^1) = 0 // * x^2

x^1*(2*x^0-5/4*x^2-1/8*x^1) = 0

x^1

(-5/4)*x^2+(-1/8)*x+2 = 0

(-5/4)*x^2+(-1/8)*x+2 = 0

DELTA = (-1/8)^2-(2*4*(-5/4))

DELTA = 641/64

DELTA > 0

x = ((641/64)^(1/2)-(-1/8))/(2*(-5/4)) or x = (-(-1/8)-(641/64)^(1/2))/(2*(-5/4))

x = -2/5*((641/64)^(1/2)+1/8) or x = -2/5*(1/8-(641/64)^(1/2))

x in { -2/5*((641/64)^(1/2)+1/8), -2/5*(1/8-(641/64)^(1/2))}

x in { -2/5*((641/64)^(1/2)+1/8), -2/5*(1/8-(641/64)^(1/2)) }

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