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(2/x)(16)=1/8x
We move all terms to the left:
(2/x)(16)-(1/8x)=0
Domain of the equation: x)16!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 8x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/x)16-(+1/8x)=0
We multiply parentheses
32x-(+1/8x)=0
We get rid of parentheses
32x-1/8x=0
We multiply all the terms by the denominator
32x*8x-1=0
Wy multiply elements
256x^2-1=0
a = 256; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·256·(-1)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*256}=\frac{-32}{512} =-1/16 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*256}=\frac{32}{512} =1/16 $
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