(2/t)-(3t/2)=7

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Solution for (2/t)-(3t/2)=7 equation:


D( t )

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

2/t-((3*t)/2) = 7 // - 7

2/t-((3*t)/2)-7 = 0

(-3/2)*t+2/t-7 = 0

2*t^-1-3/2*t^1-7*t^0 = 0

(2*t^0-3/2*t^2-7*t^1)/(t^1) = 0 // * t^2

t^1*(2*t^0-3/2*t^2-7*t^1) = 0

t^1

(-3/2)*t^2-7*t+2 = 0

(-3/2)*t^2-7*t+2 = 0

DELTA = (-7)^2-(2*4*(-3/2))

DELTA = 61

DELTA > 0

t = (61^(1/2)+7)/(2*(-3/2)) or t = (7-61^(1/2))/(2*(-3/2))

t = (61^(1/2)+7)/(-3) or t = (7-61^(1/2))/(-3)

t in { (61^(1/2)+7)/(-3), (7-61^(1/2))/(-3)}

t in { (61^(1/2)+7)/(-3), (7-61^(1/2))/(-3) }

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