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(2/9)x+5/9=3
We move all terms to the left:
(2/9)x+5/9-(3)=0
Domain of the equation: 9)x!=0determiningTheFunctionDomain (2/9)x-3+5/9=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+2/9)x-3+5/9=0
We multiply parentheses
2x^2-3+5/9=0
We multiply all the terms by the denominator
2x^2*9+5-3*9=0
We add all the numbers together, and all the variables
2x^2*9-22=0
Wy multiply elements
18x^2-22=0
a = 18; b = 0; c = -22;
Δ = b2-4ac
Δ = 02-4·18·(-22)
Δ = 1584
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1584}=\sqrt{144*11}=\sqrt{144}*\sqrt{11}=12\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{11}}{2*18}=\frac{0-12\sqrt{11}}{36} =-\frac{12\sqrt{11}}{36} =-\frac{\sqrt{11}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{11}}{2*18}=\frac{0+12\sqrt{11}}{36} =\frac{12\sqrt{11}}{36} =\frac{\sqrt{11}}{3} $
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