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(2/8)=5/(k-8)
We move all terms to the left:
(2/8)-(5/(k-8))=0
Domain of the equation: (k-8))!=0We add all the numbers together, and all the variables
k∈R
-(5/(k-8))+(+2/8)=0
We get rid of parentheses
-(5/(k-8))+2/8=0
We calculate fractions
()/8k+2k/8k=0
We multiply all the terms by the denominator
2k+()=0
We add all the numbers together, and all the variables
2k=0
k=0/2
k=0
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