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(2/5x)+(5x+5/5x)=2
We move all terms to the left:
(2/5x)+(5x+5/5x)-(2)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5x)+(+5x+5/5x)-2=0
We get rid of parentheses
2/5x+5x+5/5x-2=0
We multiply all the terms by the denominator
5x*5x-2*5x+2+5=0
We add all the numbers together, and all the variables
5x*5x-2*5x+7=0
Wy multiply elements
25x^2-10x+7=0
a = 25; b = -10; c = +7;
Δ = b2-4ac
Δ = -102-4·25·7
Δ = -600
Delta is less than zero, so there is no solution for the equation
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