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(2/5b)+1=-11
We move all terms to the left:
(2/5b)+1-(-11)=0
Domain of the equation: 5b)!=0We add all the numbers together, and all the variables
b!=0/1
b!=0
b∈R
(+2/5b)+1-(-11)=0
We add all the numbers together, and all the variables
(+2/5b)+12=0
We get rid of parentheses
2/5b+12=0
We multiply all the terms by the denominator
12*5b+2=0
Wy multiply elements
60b+2=0
We move all terms containing b to the left, all other terms to the right
60b=-2
b=-2/60
b=-1/30
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