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(2/5)x-1=(3/10)x+4
We move all terms to the left:
(2/5)x-1-((3/10)x+4)=0
Domain of the equation: 5)x!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 10)x+4)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5)x-((+3/10)x+4)-1=0
We multiply parentheses
2x^2-((+3/10)x+4)-1=0
We multiply all the terms by the denominator
2x^2*10)x+4)-((-1*10)x+4)+3=0
We add all the numbers together, and all the variables
2x^2*10)x+4)-((-10)x+4)+3=0
Wy multiply elements
20x^3-10)x+4)+3=0
We do not support expression: x^3
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