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(2/5)x+(6/5)=(-2/5)
We move all terms to the left:
(2/5)x+(6/5)-((-2/5))=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/5)x+(+6/5)-((-2/5))=0
We multiply parentheses
2x^2+(+6/5)-((-2/5))=0
We get rid of parentheses
2x^2+6/5-((-2/5))=0
We calculate fractions
2x^2=0
a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{4}=0$
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