(2/5)s-2+3(s-11)=50

Solution for (2/5)s-2+3(s-11)=50 equation:

(2/5)s-2+3(s-11)=50

We move all terms to the left:

(2/5)s-2+3(s-11)-(50)=0


Domain of the equation: 5)s!=0

s!=0/1

s!=0

s∈R


We add all the numbers together, and all the variables

(+2/5)s+3(s-11)-2-50=0

We add all the numbers together, and all the variables

(+2/5)s+3(s-11)-52=0

We multiply parentheses

2s^2+3s-33-52=0

We add all the numbers together, and all the variables

2s^2+3s-85=0

a = 2; b = 3; c = -85;
Δ = b2-4ac
Δ = 32-4·2·(-85)
Δ = 689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{689}}{2*2}=\frac{-3-\sqrt{689}}{4}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{689}}{2*2}=\frac{-3+\sqrt{689}}{4}
$