(2/5)2x+6*(2/5)3=(2/5)x+2

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Solution for (2/5)2x+6*(2/5)3=(2/5)x+2 equation: 



(2/5)2x+6(2/5)3=(2/5)x+2

We move all terms to the left:

(2/5)2x+6(2/5)3-((2/5)x+2)=0



Domain of the equation: 5)2x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5)x+2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+2/5)2x-((+2/5)x+2)+6(+2/5)3=0

We multiply parentheses

4x^2-((+2/5)x+2)+2/5*18=0

We calculate fractions


4x^2+()/5x+2)*5*18)+10x/5x+2)*5*18)=0

We calculate fractions


4x^2+(()*5x)/25x^2+2*5*18)+10x*5x)/25x^2=0

We multiply all the terms by the denominator


4x^2*25x^2+(()*5x)+2*5*18)+10x*5x)=0



We calculate terms in parentheses: +(()*5x), so:

()*5x



Wy multiply elements

100x^4+900x^2*1+(()*5x)=0



We calculate terms in parentheses: +(()*5x), so:

()*5x



We do not support expression: x^4

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