(2/5)+(5m/2)=(39/10)

Solution for (2/5)+(5m/2)=(39/10) equation:

(2/5)+(5m/2)=(39/10)

We move all terms to the left:

(2/5)+(5m/2)-((39/10))=0

We add all the numbers together, and all the variables

(+5m/2)+(+2/5)-((+39/10))=0

We get rid of parentheses

5m/2+2/5-((+39/10))=0

We calculate fractions


250m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

250m^2/()+2=0

We multiply all the terms by the denominator


250m^2+2*()=0

We add all the numbers together, and all the variables

250m^2=0

a = 250; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·250·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{500}=0$