(2/5)(y-1)=(1/5)(y-7

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Solution for (2/5)(y-1)=(1/5)(y-7 equation: 



(2/5)(y-1)=(1/5)(y-7

We move all terms to the left:

(2/5)(y-1)-((1/5)(y-7)=0



Domain of the equation: 5)(y-1)!=0

y∈R





Domain of the equation: 5)(y-7)!=0

y∈R



We add all the numbers together, and all the variables

(+2/5)(y-1)-((+1/5)(y-7)=0

We multiply parentheses ..

(+2y^2+2/5*-1)-((+1/5)(y-7)=0

We calculate fractions


((+2y^2+2*5)(y-7))/(-1)*5)(y-7)+5*)+()/(-1)*5)(y-7)+5*)=0

We calculate fractions


(((+2y^2+2*5)(y-7))*(-1)*5)y/((-1)*5)(y*(-1)*5)y-1)*5)y/((-1)*5)(y*(-1)*5)y+(-7)+5*)+()*(=0

We calculate fractions


-1)*5)y+(-7)+5*)+()*(+((((+2y^2+2*5)(y-7))*(-1)*5)y*(()/(((-1)*5)(y*(-1)*5)y*(()+(-1)*5)y*((-1)*5)(y*(-1)*5)y)/(((-1)*5)(y*(-1)*5)y*(()-1)*5)(y*(=0

We can not solve this equation

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