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(2/5)(5x-10)=-6
We move all terms to the left:
(2/5)(5x-10)-(-6)=0
Domain of the equation: 5)(5x-10)!=0We add all the numbers together, and all the variables
x∈R
(+2/5)(5x-10)-(-6)=0
We add all the numbers together, and all the variables
(+2/5)(5x-10)+6=0
We multiply parentheses ..
(+10x^2+2/5*-10)+6=0
We multiply all the terms by the denominator
(+10x^2+2+6*5*-10)=0
We get rid of parentheses
10x^2+2-10+6*5*=0
We add all the numbers together, and all the variables
10x^2=0
a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{20}=0$
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