(2/5)(5x+5x)=-20

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Solution for (2/5)(5x+5x)=-20 equation: 



(2/5)(5x+5x)=-20

We move all terms to the left:

(2/5)(5x+5x)-(-20)=0



Domain of the equation: 5)(5x+5x)!=0

x∈R



We add all the numbers together, and all the variables

(+2/5)(+10x)-(-20)=0

We add all the numbers together, and all the variables

(+2/5)(+10x)+20=0

We multiply parentheses ..

(+20x^2)+20=0

We get rid of parentheses

20x^2+20=0

a = 20; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·20·20
Δ = -1600
Delta is less than zero, so there is no solution for the equation

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