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(2/3x)+(1/6)=1/2
We move all terms to the left:
(2/3x)+(1/6)-(1/2)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/3x)+(+1/6)-(+1/2)=0
We get rid of parentheses
2/3x+1/6-1/2=0
We calculate fractions
There is no solution for this equation
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